(x^2+4)-(x-4)=0

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Solution for (x^2+4)-(x-4)=0 equation:


Simplifying
(x2 + 4) + -1(x + -4) = 0

Reorder the terms:
(4 + x2) + -1(x + -4) = 0

Remove parenthesis around (4 + x2)
4 + x2 + -1(x + -4) = 0

Reorder the terms:
4 + x2 + -1(-4 + x) = 0
4 + x2 + (-4 * -1 + x * -1) = 0
4 + x2 + (4 + -1x) = 0

Reorder the terms:
4 + 4 + -1x + x2 = 0

Combine like terms: 4 + 4 = 8
8 + -1x + x2 = 0

Solving
8 + -1x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-8' to each side of the equation.
8 + -1x + -8 + x2 = 0 + -8

Reorder the terms:
8 + -8 + -1x + x2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -1x + x2 = 0 + -8
-1x + x2 = 0 + -8

Combine like terms: 0 + -8 = -8
-1x + x2 = -8

The x term is -1x.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1x + 0.25 + x2 = -8 + 0.25

Reorder the terms:
0.25 + -1x + x2 = -8 + 0.25

Combine like terms: -8 + 0.25 = -7.75
0.25 + -1x + x2 = -7.75

Factor a perfect square on the left side:
(x + -0.5)(x + -0.5) = -7.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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